Correlation: every estimate honest and the sum still late
Eight serial tasks estimated at 8, 10 and 16 days sum to 80. Independent, four runs in five finish inside the 96 day allowance. Fully correlated they do not, and no estimate changed.
Task variation
When the sum finishes
| Sum of most likely durations | 80 days |
|---|---|
| Half finish by (P50) | 90.4 days |
| Four in five finish by (P80) | 94.6 days |
| Runs within the allowance | 86.4% |
Here is the maths
Stated assumptions
Tasks run in series. Each has a most likely duration of 10 days. The triangular distribution keeps the realistic skew: its lower edge falls by half the spread and its upper edge rises by 1.5 times the spread. There are 5,000 runs with seed 1. The allowance is fixed at 120% of the sum of most likely durations.
How correlation enters
In a share of runs equal to the correlation, every task uses the same triangular draw. In the remaining runs, task durations are independent. This mixture preserves each task's distribution and gives every pair the stated correlation. It represents one possible dependence pattern. It adds no delay and changes no task estimate.
Worked example
With 8 tasks and spread 40%, each task has estimates 8, 10 and 16 days. The sum of most likely durations is 80 days and the allowance is 96 days. Independent tasks have P80 about 94.6 days. With correlation 1, P80 is about 103.8 days. The four in five reading changes from within the allowance to beyond it.
Check it yourself
Set spread to zero. Every task takes 10 days and correlation cannot move the finish.
This is a specified mixture of independent and fully shared variation. Correlation alone does not identify a joint distribution. The model does not include resource constraints, calendars, rework or a network of dependencies. It describes this model and does not choose a completion date.
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