- Scale
- Linear on both axes, with zero drawn
- Basis
- One equal chance of winning among those invited, independent of who else bids
- Assumptions
- One margin and one preparation cost, the same for every count read
- Model version
- 1.0.0
The formula, in words
The margin is shared across equal chances of winning. Subtract the preparation cost, paid regardless of the outcome, to find expected profit from bidding.
where E(n) is the expected profit from bidding, m the margin if the bid wins, n the count invited, and c the cost of preparing the bid.
The count that stops it
The last paying count keeps expected profit above zero:
The next count is n∗+1. An exact whole ratio breaks even there; the last paying count is one below it.
A worked example
The extra invitation turns a profit into a loss with preparation costing 20,000 and winning worth 150,000.
The ratio marks where profit reaches zero:
The last whole count below it still pays:
Profit at that count, in the same currency:
At the next count, profit becomes a loss:
Show the full maths
Weight both outcomes before counting entrants
Winning leaves the margin less preparation cost; losing leaves only the preparation cost to pay. Weight each result by its chance: This uses the same cost whether the bid wins or loses. Preparation pays only when expected profit is strictly positive. Both the cost and the invited count are positive, so rearranging keeps the inequality’s direction: The last paying count is therefore the largest whole number strictly below the margin divided by cost: where n∗ is the last paying count. Rounding the ratio up and subtracting one handles both whole and fractional ratios. Zero means that no positive invited count pays. Break even is a different condition: It occurs at an invited count only when the ratio is a whole number. At that count there is no profit, so it is excluded from the paying counts. The worked example has a fractional threshold, so seven pays and the next whole count loses: With the same preparation cost and a margin of 140,000, the threshold is whole; six is the last paying count and seven breaks even: The same count, in the other lesson
One more bidder thins expected profit here and deepens the gap between the lowest estimate and true cost in the linked lesson. More competition can discourage entry while making the lowest bid more likely to underestimate cost.
Why the lowest bid tends to be an underestimate
What this does not model
No unequal bidders or changing preparation costs. No learning, reserve price or bid subsidy. No prediction of entry.
What the sweep checks
Only the count changes, in whole steps; each verdict uses the same margin and preparation cost as the finding.
Source basis
Nicola Dimitri, Gustavo Piga and Giancarlo Spagnolo, Handbook of Procurement: costly preparation changes the participation a buyer can expect; Paul Milgrom, Putting Auction Theory to Work: entry costs meet diminishing gains from another entrant. Paul Klemperer, Auctions: Theory and Practice: entry responds to incentives and can lower common value auction revenue.
Calculation version
1.0.0