One occupied cycle
Let Q be batch units, S setup seconds, p run seconds per unit, and D hourly demand. Capacity divides units by all occupied time: C(Q)=S+Qp3600Q. Required load is the fraction of available time the demand would occupy: u=3600QD(S+Qp).
The strict crossing
Q>3600−DpDS(3600−Dp>0). The first whole quantity strictly above the quotient has spare capacity. Equality receives its own reading, and a nonpositive denominator means no finite batch is strictly above demand.
The opening ledger
- Run work: 40×60=2400 seconds; cycle time: 1800+2400=4200 seconds.
- Capacity: 42003600×40=34.285714285714285 units/hour, displayed as 34.3; load: 3600×4040×4200=1.1666666666666667, displayed as 116.7%.
- Crossing: 3600−40×6040×1800=60 units; 60 ties at 40.0 units/hour, and 61 first exceeds demand at 40.21978021978022, displayed as 40.2.
Source basis
Gerard Cachon and Christian Terwiesch derive setup-adjusted batch capacity in Matching Supply with Demand: An Introduction to Operations Management, fourth edition, 2018, chapter 5. Wallace Hopp and Mark Spearman distinguish process batches from transfer batches and describe their capacity effect in Factory Physics, third edition, 2008, section 9.4.2.
- Scale
- Whole batches checked from 1 to 1,000; continuous guide between them, exact integer comparison
- Basis
- One sequential workstation, one occupied setup per process batch, identical run time per unit
- Assumptions
- Repeated identical cycles, constant demand, all completed units counted on the same basis
- Model version
- 1.0.0